Monday, May 24, 2010

Speed P6 A001

6. Two sisters, Melissa and Nicole, started brisk-walking at 6.45 a.m. from their house to a nearby park. Melissa walked at an average speed of 90 m/min while Nicole's average speed was 60 m/min. After arriving at the park, Melissa rested for 10 minutes and then walked back home. If Melissa met Nicole at 7.40 a.m. on her return journey, what was the distance between their house and the park?

                 55 min   Time taken by Melissa.
    !---------------------!
6.45 a.m.              7.40 a.m.

55 – 10 = 45 min     Time taken by Nicole.

90 x 45 = 4050 m    Distance travelled by Melissa.

60 x 55 = 3300 m    Distance travelled by Nicole.

4050 – 3300 = 750  Difference in distance travelled.
750 ÷ 2 = 375 m     As Melissa had turned back (to and fro).

3300 + 375 = 3675 m

The distance between their house and the park was 3 675 m.

No comments:

Post a Comment