Janice had three boxes, A, B and C, containing a total of 1512 pearls. The number of pearls in Box A to the total number of pearls was 2 : 7. Janice sold 190 pearls from Box B and sold ¼ of the pearls in Box C. The number of pearls left in Box B to the number of pearls left in Box C was 2 : 1. How many pearls were there in Box C at first? [5 marks][Answer given: 356 pearls]
5/7 x 1512 = 1080
B [][][][][][] [ 190 ] ] 1080
C [][][] [] ]
10 u --> 1080 - 190 = 890
4 u --> 4/10 x 890 = 356 pearls
It was 356 pearls.
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